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Question Number 118491 by Lordose last updated on 18/Oct/20
...⧫AdvancedCalculus⧫...Evaluate::Ω=∫0∞secθ4tan2θ+5dθ...♠LϕrD∅sE♠......♣GooDLucK♣
Answered by MJS_new last updated on 18/Oct/20
∫secθ5+4tan2θdθ==sign(cosx)55∫dθ1−15sin2θ==sign(cosx)55F(x∣15)+C⇒Ωisnotdefined[plotsecθ5+4tan2θandyou′llseewhy]
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