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Question Number 118545 by I want to learn more last updated on 18/Oct/20

Commented by Tawa11 last updated on 15/Sep/21

nice

nice

Answered by mr W last updated on 18/Oct/20

Commented by mr W last updated on 18/Oct/20

a=((72)/2)=36  (a+b)^2 =(a−b)^2 +(100−a−b)^2   144b=(64−b)^2   64^2 −272b+b^2 =0  ⇒b=136±120 ⇒b=16  [100−a−b−(√((a+c)^2 −(a−c)^2 ))]^2 +(72−b−c)^2 =(b+c)^2   (48−12(√c))^2 +(56−c)^2 =(16+c)^2   48^2 −2×12×48(√c)+56^2 =16^2   9−2(√c)=0  ⇒c=((81)/4)

a=722=36(a+b)2=(ab)2+(100ab)2144b=(64b)2642272b+b2=0b=136±120b=16[100ab(a+c)2(ac)2]2+(72bc)2=(b+c)2(4812c)2+(56c)2=(16+c)24822×12×48c+562=16292c=0c=814

Commented by I want to learn more last updated on 25/Oct/20

Thanks sir, I really appreciate.

Thankssir,Ireallyappreciate.

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