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Question Number 119000 by bramlexs22 last updated on 21/Oct/20

lim_(x→∞)  x^(3/2)  sin 2x =?

limxx32sin2x=?

Commented by MJS_new last updated on 21/Oct/20

not defined  x^(3/2) →∞∧−1≤sin 2x ≤1

notdefinedx321sin2x1

Answered by Bird last updated on 21/Oct/20

sin(2x)ossilate between−1 and1  so no limit for this

sin(2x)ossilatebetween1and1sonolimitforthis

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