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Question Number 119000 by bramlexs22 last updated on 21/Oct/20
limx→∞x32sin2x=?
Commented by MJS_new last updated on 21/Oct/20
notdefinedx32→∞∧−1⩽sin2x⩽1
Answered by Bird last updated on 21/Oct/20
sin(2x)ossilatebetween−1and1sonolimitforthis
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