All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 119021 by A8;15: last updated on 21/Oct/20
Answered by MJS_new last updated on 21/Oct/20
∫sinxsinx+cosxdx=∫tanx1+tanxdx=[t=tanx→dx=2tt4+1dt]=2∫t2(t+1)(t4+1)dtnowdecomposeIgetln(t+1)−1−24ln(t2−2t+1)−1+24ln(t2+2t+1)++12(arctan(2t−1)−arctan(2t+1))+C
Terms of Service
Privacy Policy
Contact: info@tinkutara.com