Question and Answers Forum

All Questions      Topic List

Integration Questions

Previous in All Question      Next in All Question      

Previous in Integration      Next in Integration      

Question Number 119070 by benjo_mathlover last updated on 22/Oct/20

$$\int \frac{x^2-x+6}{x^3+3x}dx$$$$\int \frac{5x^2+3x-2}{x^3+2x^2}dx$$

Answered by Olaf last updated on 22/Oct/20

$$\mathrm{F}\left(x\right)=\int \frac{x^2-x+6}{x^3+3x}dx$$$$\mathrm{F}\left(x\right)=\int (\frac{2}{x}-\frac{x+1}{x^2+3})dx$$$$\mathrm{F}\left(x\right)=2\ln \mid x\mid -\frac{1}{2}\ln (x^2+3)-\frac{1}{\sqrt{3}}\arctan \left(\frac{x}{\sqrt{3}}\right)$$

Answered by Olaf last updated on 22/Oct/20

$$\mathrm{G}\left(x\right)=\int \frac{5x^2+3x-2}{x^3+2x^2}dx$$$$\mathrm{G}\left(x\right)=\int (-\frac{1}{x^2}+\frac{2}{x}+\frac{3}{x+2})dx$$$$\mathrm{G}\left(x\right)=\frac{1}{x}+2\ln \mid x\mid +3\ln \mid x+2\mid$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com