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Question Number 119133 by Cristina last updated on 22/Oct/20
Informatica(11110000)2=0∙20+0∙21+0∙22+0∙23+1∙24+1∙25+1∙26+1∙27==0∙1+0∙2+0∙4+0∙8+1∙16+1∙32+1∙64+1∙128=0+0+0+0+16+32+64+128=(240)10(11000101)2=1∙20+0∙21+1∙22+0∙23+0∙24+0∙25+1∙26+1∙27==1∙1+0∙2+1∙4+0∙8+0∙16+0∙32+1∙64+1∙128=(197)10(01101001)2=
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