Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 119141 by Engr_Jidda last updated on 22/Oct/20

Answered by TANMAY PANACEA last updated on 23/Oct/20

$$\frac{d^{2}x}{{dt}^2}+\frac{dy}{dt}=-sint$$$$\frac{d^{2}x}{{dt}^2}+4\frac{dx}{dt}+3x-sint=-sint$$$$x=e^{mt}$$$$(m^2+4m+3)e^{mt}=0$$$$e^{mt}\ne 0$$$$(m+1)(m+3)=0\to m=-1,-3$$$$x={Ae}^{-t}+{Be}^{-3t}$$$$y=cost-\frac{dx}{dt}$$$$y=cost+{Ae}^{-t}+3{Be}^{-3t}$$

Commented by Engr_Jidda last updated on 22/Oct/20

$$\mathrm{thank}\mathrm{you}\mathrm{very}\mathrm{much}\mathrm{sir}$$

Commented by TANMAY PANACEA last updated on 22/Oct/20

$$mostwelcome$$

Commented by Engr_Jidda last updated on 22/Oct/20

$$\mathrm{but}\mathrm{pls}\mathrm{how}\mathrm{do}\mathrm{y}\mathrm{becomes}\mathrm{sint}-\frac{\mathrm{dx}}{\mathrm{dt}}?$$

Commented by TANMAY PANACEA last updated on 23/Oct/20

$$sorry..Typo...itshouldbey=cost-\frac{dx}{dt}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com