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Question Number 119506 by bemath last updated on 25/Oct/20
cosπ5cosx+sinπ5sinx⩽22
Answered by 1549442205PVT last updated on 25/Oct/20
cosπ5cosx+sinπ5sinx⩽22⇔cos(x−π5)⩽cosπ4⇔x−π5⩾π4+2mπ⇔π4+2mπ⩽x⩽7π4+2mπ
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