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Question Number 119527 by joki last updated on 25/Oct/20

Commented by benjo_mathlover last updated on 25/Oct/20

$$\left(a\right)P\left(male/secondaryeducation\right)=\frac{P(M\cap E)}{P\left(E\right)}$$$$=\frac{28}{28+50}=\frac{28}{78}=\frac{14}{39}.$$

Commented by joki last updated on 25/Oct/20

$$b?$$

Answered by benjo_mathlover last updated on 25/Oct/20

$$\left(b\right)P\left(A/B\right)=\frac{P(A\cap B)}{P\left(B\right)}=\frac{45+50}{45+50+17}$$$$A:doesnothavecollegedegree$$$$B:female$$

Commented by joki last updated on 25/Oct/20

$$number2.98sir,idontunderstand.thankssir$$

Answered by benjo_mathlover last updated on 25/Oct/20

$$P\left(W\right)=P(A\cap B\cap C\cap D)+P(A\cap B\cap C^c\cap D)$$$$+P(A\cap B^c\cap C\cap D)$$

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