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Question Number 119629 by 9764954060 last updated on 25/Oct/20

Answered by TANMAY PANACEA last updated on 25/Oct/20

$${ax}^2+bx+c=0$$$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$$$soherex=\frac{-3\pm \sqrt{3^2-4\times 2\times 7}}{2\times 2}=\frac{-3\pm \sqrt{-47}}{4}$$$$x=\frac{-3\pm i\sqrt{47}}{4}[i=\sqrt{-1}]$$

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