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Question Number 120118 by sarahvalencia last updated on 30/Oct/20

Commented by Dwaipayan Shikari last updated on 29/Oct/20

$N e t r e s i s t a n c e 10 k Ω$ $I = \frac{50}{10 . 10^{3}} = 5 \times 10^{- 3} A$
Commented by Dwaipayan Shikari last updated on 29/Oct/20

$A t f i r s t R_{1} = 4 Ω + 6 Ω = 10 k Ω (s e r i e s)$ $R_{1} a n d 30 k Ω a r e i n p a r a l l e l$ $R_{2} = {(\frac{1}{R_{1}} + \frac{1}{30})}^{- 1} = \frac{15}{2} k Ω$ $R_{2} ∣∣ 15 k Ω R_{3} = {(\frac{1}{R_{2}} + \frac{1}{15})}^{- 1} = 5 k Ω$ $20 k Ω ∣∣ 5 k Ω s o R_{4} = {(\frac{1}{20} + \frac{1}{5})}^{- 1} = 4 k Ω$ $R_{4} a n d R_{3} i s i n s e r i e s R_{5} = R_{3} + R_{4} = 9 k Ω$ $R_{6} = 1 k Ω a n d s e r i e s w i t h R_{5} = 9 k Ω$ $R_{n e t} = 9 + 1 = 10 k Ω$
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