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Question Number 120140 by help last updated on 29/Oct/20

Answered by nimnim last updated on 29/Oct/20

(x,y,z)=(2,4,−3)

(x,y,z)=(2,4,−3)

Commented by help last updated on 29/Oct/20

solution please

solutionplease

Answered by nimnim last updated on 29/Oct/20

Breaking the brackets, we get 5x+10y−12x−16z−2x−6y+10z=16 −9x+4y−6z=16.............(i) 6x−2y+3x−6z+8x−12y+4z=−16 17x−14y−2z=−16........(ii) 4y−8z+4x−8y−6−3x−12y+6z=62 x−16y−2z=−56........(iii) (ii)−(iii)⇒16x+2y=40⇒8x+y=20.....(iv) (i)−3(iii)⇒−12x+52y=184⇒−3x+13y=46....(v) from (iv)and (v) x=2 and y=4 (iii)⇒2−16(4)−2z=−56 ⇒z=−3

Breakingthebrackets,weget5x+10y−12x−16z−2x−6y+10z=16−9x+4y−6z=16.............(i)6x−2y+3x−6z+8x−12y+4z=−1617x−14y−2z=−16........(ii)4y−8z+4x−8y−6−3x−12y+6z=62x−16y−2z=−56........(iii)(ii)−(iii)⇒16x+2y=40⇒8x+y=20.....(iv)(i)−3(iii)⇒−12x+52y=184⇒−3x+13y=46....(v)from(iv)and(v)x=2andy=4(iii)⇒2−16(4)−2z=−56⇒z=−3

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