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Question Number 12019 by Nayon last updated on 09/Apr/17

Answered by ajfour last updated on 10/Apr/17

Commented by ajfour last updated on 10/Apr/17

AC^( 2) +BD^2 =CF^( 2) +h^2 +ED^2 +h^2 =(CD−CE)^2 +h^2 +(CD−DF)^2 +h^2 = CD^2 +CE^2 +CD^2 +DF^( 2) +h^2 +h^2 −2CD(CE+DF) = (CE^2 +h^2 )+(DF^( 2) +h^2 )+2CD^2 −2CD(CD−AB) = BC^( 2) +AD^2 +2AB.CD

AC2+BD2=CF2+h2+ED2+h2=(CD−CE)2+h2+(CD−DF)2+h2=CD2+CE2+CD2+DF2+h2+h2−2CD(CE+DF)=(CE2+h2)+(DF2+h2)+2CD2−2CD(CD−AB)=BC2+AD2+2AB.CD

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