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Question Number 120322 by sdfg last updated on 30/Oct/20

Commented by TANMAY PANACEA last updated on 30/Oct/20

$d o x^{'} m e a n s = \frac{d x}{d t} p l s . . .$
Commented by Dwaipayan Shikari last updated on 30/Oct/20

$\frac{d x}{d t} = x - 2 y - t^{2}$ $\Rightarrow x = x t - 2 y t - \frac{t^{3}}{3} + C$ $O r$ $\frac{d x}{d y} = x - 2 y - t^{2} \Rightarrow x = x y - y^{2} - t^{2} y + C$
Commented by prakash jain last updated on 31/Oct/20

$Second Step :$ $y is a constant or a function of t ?$
	Answered by mr W last updated on 31/Oct/20

	$x = {a t}^{2} + b t + c$ $y = {p t}^{2} + q t + r$ $z = {u t}^{2} + v t + w$ $2 a t + b = {a t}^{2} + b t + c - 2 {p t}^{2} - 2 q t - 2 r - t^{2}$ $(a - 2 p - 1) t^{2} + (b - 2 a - 2 q) t - b + c - 2 r = 0$ $\Rightarrow a - 2 p - 1 = 0 (1)$ $\Rightarrow - 2 a + b - 2 q = 0 (2)$ $\Rightarrow - b + c - 2 r = 0 (3)$ $. . . . . .$
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