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Question Number 120595 by fajri last updated on 01/Nov/20
$$ \\ $$$${Solution}\:{from}\:{Differential}\:{Equation}\:{System}\:: \\ $$$$ \\ $$$$\left\{_{{x}_{\mathrm{2}} ^{'} \:=\:\:\mathrm{2}{x}_{\mathrm{1}} \:−\:\mathrm{3}{x}_{\mathrm{2}} \:\:,\:{x}_{\mathrm{2}} \:\left(\mathrm{0}\right)\:=\:−\mathrm{1}} ^{{x}_{\mathrm{1}} ^{'} \:=\:\mathrm{2}{x}_{\mathrm{1}} −\:\mathrm{2}{x}_{\mathrm{2}} \:\:\:\:,\:{x}_{\mathrm{1}} \left(\mathrm{0}\right)\:=\:\mathrm{1}} \right. \\ $$$$ \\ $$$$ \\ $$$$ \\ $$