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Question Number 120676 by I want to learn more last updated on 01/Nov/20

Commented by som(math1967) last updated on 02/Nov/20

BC+AC−AB  =5+6−3=8unit

BC+ACAB=5+63=8unit

Commented by som(math1967) last updated on 02/Nov/20

Commented by som(math1967) last updated on 02/Nov/20

CD+DE+EC  =CD+DM+ME+EC  =CD+DN+OE+EC ★  =CN+CO  =AC−AN+BC−BO  =AC+BC−(AL+BL)★★  =AC+BC−AB  =6+5−3=8unit  ★DM=DN,ME=OE  ★★AN=AL,BO=BL

CD+DE+EC=CD+DM+ME+EC=CD+DN+OE+EC=CN+CO=ACAN+BCBO=AC+BC(AL+BL)=AC+BCAB=6+53=8unitDM=DN,ME=OEAN=AL,BO=BL

Commented by I want to learn more last updated on 02/Nov/20

Thanks sir

Thankssir

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