Find the singular point in the differential equation : (x^3 − x^2 − 9x + 9)(d^2 y/dx^2 ) +2x(dy/dx) + (x − 3)y = 0


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Question Number 120811 by fajri last updated on 03/Nov/20

$F i n d t h e s i n g u l a r p o i n t i n t h e$ $d i f f e r e n t i a l e q u a t i o n :$ $(x^{3} - x^{2} - 9 x + 9) \frac{d^{2} y}{{d x}^{2}} + 2 x \frac{d y}{d x} + (x - 3) y = 0$
	Answered by 675480065 last updated on 03/Nov/20

	$(x + 1) (x - 3) (x + 3) \frac{d^{2} y}{{d x}^{2}} + 2 x \frac{d y}{d x} + (x - 3) y = 0$ $S . p$ $(x + 1) (x - 3) (x + 3) = 0$ $x = - 1, 3, - 3$
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