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Question Number 12087 by tawa last updated on 12/Apr/17

$$\mathrm{In}\mathrm{how}\mathrm{many}\mathrm{ways}\mathrm{can}10\mathrm{objects}\mathrm{be}\mathrm{split}\mathrm{into}\mathrm{two}\mathrm{groups}\mathrm{containing}$$$$4\mathrm{and}6\mathrm{objects}\mathrm{respectively}?$$

Answered by sandy_suhendra last updated on 12/Apr/17

$$10\mathrm{C}4=\frac{10!}{6!4!}=210$$$$\mathrm{or}10\mathrm{C}6=210$$

Commented by tawa last updated on 12/Apr/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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