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Question Number 120946 by mnjuly1970 last updated on 04/Nov/20

Answered by Jamshidbek2311 last updated on 04/Nov/20

((sinβ)/(sin20°))=((sin(110°−β))/(sin10°)) ⇒ β=80°

$$\frac{{sin}\beta}{{sin}\mathrm{20}°}=\frac{{sin}\left(\mathrm{110}°−\beta\right)}{{sin}\mathrm{10}°}\:\Rightarrow\:\beta=\mathrm{80}° \\ $$$$ \\ $$

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