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Question Number 12106 by tawa last updated on 13/Apr/17

Answered by FilupS last updated on 13/Apr/17

$$\mathrm{\Sigma }{a}_n\mathrm{diverges}\mathrm{if}:\underset{n\to \mathrm{\infty }}{\lim }{a}_n\ne 0$$$$\mathrm{\Sigma }{ca}_n=c\mathrm{\Sigma }{a}_n$$$$\therefore c\mathrm{\Sigma }{a}_n\mathrm{diverges}$$$$\because \mathrm{\Sigma }{a}_n\to \pm \mathrm{\infty }$$

Commented by tawa last updated on 13/Apr/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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