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Question Number 121077 by zakirullah last updated on 05/Nov/20

Commented by zakirullah last updated on 05/Nov/20

please help??⇈⇑

$$\boldsymbol{{please}}\:\boldsymbol{{help}}??\upuparrows\Uparrow \\ $$

Answered by liberty last updated on 05/Nov/20

Q1) n(A∪B)=n(A)+n(B)−n(A∩B)                                = 28+32−10=50

$$\left.\mathrm{Q1}\right)\:\mathrm{n}\left(\mathrm{A}\cup\mathrm{B}\right)=\mathrm{n}\left(\mathrm{A}\right)+\mathrm{n}\left(\mathrm{B}\right)−\mathrm{n}\left(\mathrm{A}\cap\mathrm{B}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\mathrm{28}+\mathrm{32}−\mathrm{10}=\mathrm{50} \\ $$

Commented by zakirullah last updated on 05/Nov/20

thanks but solve and explain other questions

$$\boldsymbol{{thanks}}\:\boldsymbol{{but}}\:\boldsymbol{{solve}}\:\boldsymbol{{and}}\:\boldsymbol{{explain}}\:\boldsymbol{{other}}\:\boldsymbol{{questions}} \\ $$

Answered by Dwaipayan Shikari last updated on 05/Nov/20

Q2)  n(A∩B)=n(A)+n(B)−n(A∩B)                      = 8+15−18=5

$$\left.{Q}\mathrm{2}\right)\:\:{n}\left({A}\cap{B}\right)={n}\left({A}\right)+{n}\left({B}\right)−{n}\left({A}\cap{B}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\mathrm{8}+\mathrm{15}−\mathrm{18}=\mathrm{5} \\ $$

Answered by Dwaipayan Shikari last updated on 05/Nov/20

n(P∪M)=n(P)+n(M)−n(P∩M)  20   = n(P)+12−4  n(P)=12

$${n}\left({P}\cup{M}\right)={n}\left({P}\right)+{n}\left({M}\right)−{n}\left({P}\cap{M}\right) \\ $$$$\mathrm{20}\:\:\:=\:{n}\left({P}\right)+\mathrm{12}−\mathrm{4} \\ $$$${n}\left({P}\right)=\mathrm{12} \\ $$

Commented by zakirullah last updated on 05/Nov/20

great!

$$\boldsymbol{{great}}! \\ $$

Answered by Ar Brandon last updated on 05/Nov/20

Q3.  n(M∪P)=20, n(M)=12, n(M∩P)=4  n(M∪P)=n(M)+n(P)−n(M∩P)    20=12+n(P)−4 ⇒ n(P)=12

$$\mathrm{Q3}. \\ $$$$\mathrm{n}\left(\mathrm{M}\cup\mathrm{P}\right)=\mathrm{20},\:\mathrm{n}\left(\mathrm{M}\right)=\mathrm{12},\:\mathrm{n}\left(\mathrm{M}\cap\mathrm{P}\right)=\mathrm{4} \\ $$$$\mathrm{n}\left(\mathrm{M}\cup\mathrm{P}\right)=\mathrm{n}\left(\mathrm{M}\right)+\mathrm{n}\left(\mathrm{P}\right)−\mathrm{n}\left(\mathrm{M}\cap\mathrm{P}\right) \\ $$$$\:\:\mathrm{20}=\mathrm{12}+\mathrm{n}\left(\mathrm{P}\right)−\mathrm{4}\:\Rightarrow\:\mathrm{n}\left(\mathrm{P}\right)=\mathrm{12} \\ $$

Commented by zakirullah last updated on 05/Nov/20

thanks

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Answered by TANMAY PANACEA last updated on 05/Nov/20

Q3)n(m∪p)=n(m)+n(p)−n(m∩p)  20=12+n(p)−4  n(p)=12

$$\left.{Q}\mathrm{3}\right){n}\left({m}\cup{p}\right)={n}\left({m}\right)+{n}\left({p}\right)−{n}\left({m}\cap{p}\right) \\ $$$$\mathrm{20}=\mathrm{12}+{n}\left({p}\right)−\mathrm{4} \\ $$$${n}\left({p}\right)=\mathrm{12} \\ $$

Commented by zakirullah last updated on 05/Nov/20

great work sir

$$\boldsymbol{{great}}\:\boldsymbol{{work}}\:\boldsymbol{{sir}} \\ $$

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