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Question Number 121100 by Ar Brandon last updated on 05/Nov/20

	Answered by TANMAY PANACEA last updated on 05/Nov/20

	$\frac{l o g x}{x (y + z - x)} = \frac{l o g y}{y (z + x - y)} = \frac{l o g z}{z (x + y - z)} = k$ $l o g x = k x (y + z - x)$ $l o g y = k y (z + x - y)$ $l o g z = k z (x + y - z)$ $A) x^{y} y^{x} = p$ $y l o g x + x l o g y = l o g p$ $y k x (y + z - x) + k x y (z + x - y) = l o g p$ $x y k (y + z - x + z + x - y)$ $x y k (2 z) = 2 x y z \times k$ $y^{z} z^{y} = Q$ $z l o g y + y l o g z = l o g Q$ $z k y (z + x - y) + y k z (x + y - z) = l o g Q$ $y z k (2 x)$ $2 x y z k$ $s o l o g p = l o g Q$ $s o o p t i o n A i s c o r r e c t . . .$ $p l s c h e c k s a m e w a y o p t i o n (B, C, D) p l s$
	Commented by Ar Brandon last updated on 05/Nov/20
	Thank you Sir. It is a multiple correct choice type question.
	Commented by TANMAY PANACEA last updated on 05/Nov/20

	$m o s t w e l c o m e s i r$
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