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Question Number 121188 by mathocean1 last updated on 05/Nov/20

N is written 158b687a in base 10.  with  a<b.  show that N≡2+a[4]

$${N}\:{is}\:{written}\:\mathrm{158}{b}\mathrm{687}{a}\:{in}\:{base}\:\mathrm{10}. \\ $$ $${with}\:\:{a}<{b}. \\ $$ $${show}\:{that}\:{N}\equiv\mathrm{2}+{a}\left[\mathrm{4}\right] \\ $$

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