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Question Number 121314 by Bird last updated on 06/Nov/20
findlimn→+∞∫0ncos(nx)x2+n2dx
Answered by mathmax by abdo last updated on 06/Nov/20
In=∫0ncos(nx)x2+n2dxchangementx=ntgiveIn=∫01cos(n2t)n2(1+t2)ndt=1n∫01cos(n2t)t2+1dt⇒∣In∣⩽1n∫01dtt2+1⇒∣In∣⩽π4n→0⇒limn→+∞In=0
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