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Question Number 12144 by rish@bh last updated on 14/Apr/17
11+12+14+21+22+24+31+32+34+.....∞=?
Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 14/Apr/17
nn4+n2+1=n(n2+1)2−n2=n(n2+n+1)(n2−n+1)=12.(n2+n+1)−(n2−n+1)(n2+n+1)(n2−n+1)=12(1n2−n+1−1n2+n+1)LHS=12[11−13+13−17+17−113.....−1n2+n+1]==12.(1−1n2+n+1)=n2+n2(n2+n+1)limx→∝LHS=12.◼
Commented by rish@bh last updated on 14/Apr/17
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