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Question Number 121442 by bramlexs22 last updated on 08/Nov/20

Answered by liberty last updated on 08/Nov/20

Answered by Don08q last updated on 09/Nov/20

$$y^2-3xy+x^2-x+y+9=0$$$$y^2-2xy+x^2-xy+y-x+9=0$$$${(y-x)}^2+(y-x)+9=xy$$$${\left(2\right)}^2+\left(2\right)+9=xy$$$$xy=15$$$$$$

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