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Question Number 121506 by benjo_mathlover last updated on 08/Nov/20

  lim_(x→0)  (x+e^(x/2) )^(2/x)  ?

limx0(x+ex2)2x?

Answered by liberty last updated on 09/Nov/20

L = lim_(x→0)  (x+e^(x/2) )^(2/x)   ln L = lim_(x→0)  ((2ln (x+e^(x/2) ))/x)   ln L = lim_(x→0) ((2(((1+(1/2)e^(x/2) )/(x+e^(x/2) ))))/1)  ln L = 2((3/2)) = 3 ⇒ L = e^3 .▲

L=limx0(x+ex2)2xlnL=limx02ln(x+ex2)xlnL=limx02(1+12ex2x+ex2)1lnL=2(32)=3L=e3.

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