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Question Number 121552 by I want to learn more last updated on 09/Nov/20

Commented by mr W last updated on 10/Nov/20

$$4ways:$$$$8+7+2+1=6+5+4+3$$$$8+6+3+1=7+5+4+2$$$$8+5+4+1=7+6+3+2$$$$8+5+3+2=7+6+4+1$$

Commented by I want to learn more last updated on 10/Nov/20

$$\mathrm{Thanks}\mathrm{sir}.$$

Commented by I want to learn more last updated on 10/Nov/20

$$\mathrm{I}\mathrm{thought}\mathrm{we}\mathrm{can}\mathrm{have}\mathrm{a}\mathrm{formular}\mathrm{before}.$$

Commented by mr W last updated on 10/Nov/20

$$thecoefficientofterm{x}^{18}in$$$$(1+x)(1+x^2)(1+x^3)...(1+x^8)$$$$is14,i.e.wehavetotally\frac{14}{2}=7ways.$$$$amongthemthreewayswith$$$$3+5numbersandfourwayswith$$$$4+4numbers.$$

Commented by I want to learn more last updated on 19/Nov/20

$$\mathrm{Thanks}\mathrm{sir},\mathrm{please}\mathrm{how}\mathrm{is}\mathrm{it}\mathrm{coefficient}\mathrm{of}{\mathrm{x}}^{18}$$

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