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Question Number 121707 by rs4089 last updated on 11/Nov/20

Answered by Dwaipayan Shikari last updated on 11/Nov/20

$${\int }_1^2{\int }_1^3{xy}^{2}dxdy$$$${\int }_1^2{y}^2{\left[\frac{x^2}{2}\right]}_1^{3}dy$$$$=\frac{8}{2}{\int }_1^2{y}^{2}dy=4(\frac{8}{3}-\frac{1}{3})=\frac{28}{3}=9.33333$$

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