Question and Answers Forum

All Questions      Topic List

Limits Questions

Previous in All Question      Next in All Question      

Previous in Limits      Next in Limits      

Question Number 121726 by oustmuchiya@gmail.com last updated on 11/Nov/20

Answered by TANMAY PANACEA last updated on 11/Nov/20

6n^3 >4n^3   also 2^n >2  so  6n^3 +2^n >4n^3 +2  so lim_(nā†’āˆž)  ((6n^3 +2^n )/(4n^3 +2))=āˆž

$$\mathrm{6}{n}^{\mathrm{3}} >\mathrm{4}{n}^{\mathrm{3}} \:\:{also}\:\mathrm{2}^{{n}} >\mathrm{2} \\ $$$${so}\:\:\mathrm{6}{n}^{\mathrm{3}} +\mathrm{2}^{{n}} >\mathrm{4}{n}^{\mathrm{3}} +\mathrm{2} \\ $$$${so}\:\mathrm{li}\underset{{n}\rightarrow\infty} {\mathrm{m}}\:\frac{\mathrm{6}{n}^{\mathrm{3}} +\mathrm{2}^{{n}} }{\mathrm{4}{n}^{\mathrm{3}} +\mathrm{2}}=\infty \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com