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Question Number 121726 by oustmuchiya@gmail.com last updated on 11/Nov/20

Answered by TANMAY PANACEA last updated on 11/Nov/20

$$6n^3>4n^{3}also{2}^n>2$$$$so6n^3+2^n>4n^3+2$$$$so\mathrm{li}\underset{n\to \mathrm{\infty }}{\mathrm{m}}\frac{6n^3+2^n}{4n^3+2}=\mathrm{\infty }$$

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