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Question Number 121825 by bemath last updated on 12/Nov/20
∫dxx−4x?
Commented by bemath last updated on 12/Nov/20
∫dxx(x−4)dx=2∫d(x−4)x−4=2ln∣x−4∣+c
Answered by Dwaipayan Shikari last updated on 12/Nov/20
∫dxx(x−4)=2∫12x.1x−4dx=2log(x−4)+C
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