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Question Number 121889 by oustmuchiya@gmail.com last updated on 12/Nov/20

Answered by Dwaipayan Shikari last updated on 12/Nov/20

(1+ax)^b =1+48x+1008x^2 +...  ab=48  a^2 ((b(b−1))/2)=1008  ((a(b−1))/2)=21⇒a=6 ,b=8

(1+ax)b=1+48x+1008x2+...ab=48a2b(b1)2=1008a(b1)2=21a=6,b=8

Answered by TANMAY PANACEA last updated on 12/Nov/20

(1+2x+3x^2 )(1+2x)^7   (1+2x+3x^2 ){1+7C_1 (2x)+7C_2 (2x)^2 +7C_3 (2x)^3 +othdr terms}  =1×7C_3 (2x)^3 +2x×7C_2 (2x)^2 +3x^2 ×7C_1 (2x)  =x^3 (7C_3 ×2^3 +2×7C_2 ×2^2 +3×7C_1 ×2)   pls calculate

(1+2x+3x2)(1+2x)7(1+2x+3x2){1+7C1(2x)+7C2(2x)2+7C3(2x)3+othdrterms}=1×7C3(2x)3+2x×7C2(2x)2+3x2×7C1(2x)=x3(7C3×23+2×7C2×22+3×7C1×2)plscalculate

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