Question Number 121913 by Jamshidbek2311 last updated on 12/Nov/20
$$\begin{cases}{{x}^{\mathrm{2}} +{y}=\mathrm{36}}\\{{x}+{y}^{\mathrm{2}} =\mathrm{25}\:\:{x}=?\:{y}=?}\end{cases} \\ $$
Answered by MJS_new last updated on 12/Nov/20
$$\left(\mathrm{1}\right)\:{y}=\mathrm{36}−{x}^{\mathrm{2}} \\ $$$$\Rightarrow \\ $$$$\left(\mathrm{2}\right)\:{x}^{\mathrm{4}} −\mathrm{72}{x}^{\mathrm{2}} +{x}+\mathrm{1271}=\mathrm{0} \\ $$$$\mathrm{and}\:\mathrm{this}\:\mathrm{can}\:\mathrm{only}\:\mathrm{be}\:\mathrm{solved}\:\mathrm{approximately} \\ $$
Commented by MJS_new last updated on 12/Nov/20
$$...\mathrm{of}\:\mathrm{course}\:\mathrm{it}\:{is}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{exactly}\:\mathrm{solve}\:\mathrm{any} \\ $$$$\mathrm{polynome}\:\mathrm{of}\:\mathrm{degree}\:\mathrm{4}\:\mathrm{but}\:\mathrm{in}\:\mathrm{this}\:\mathrm{case}\:\mathrm{you} \\ $$$$\mathrm{cannot}\:\mathrm{handle}\:\mathrm{the}\:\mathrm{exact}\:\mathrm{solutions} \\ $$