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Question Number 122081 by bobhans last updated on 14/Nov/20

 solve  { ((∣x−1∣+∣y−1∣=1)),((∣x−1∣−y=−5)) :}

solve{x1+y1∣=1x1y=5

Answered by mathmax by abdo last updated on 14/Nov/20

⇒ { ((∣x−1∣=y−5)),((∣y−1∣+y =6     let solve ∣y−1∣+y =6  withy≥5)) :}  ⇒∣y−1∣+y−6=0  if y≥1  e⇒y−1+y−6=0 ⇒2y−7=0 ⇒y=(7/2) (not solution)  if y≤1   e⇒1−y+y−6 =0 ⇒−5=0 impossible ⇒no solution for this  system

{x1∣=y5y1+y=6letsolvey1+y=6withy5⇒∣y1+y6=0ify1ey1+y6=02y7=0y=72(notsolution)ify1e1y+y6=05=0impossiblenosolutionforthissystem

Answered by MJS_new last updated on 14/Nov/20

∣x−1∣−y=−5 ⇒ y=∣x−1∣+5  insert in (1)  ∣x−1∣+∣∣x−1∣+5−1∣=1  ∣x−1∣+∣∣x−1∣+4∣=1  ∣x−1∣+∣x−1∣+4=1  2∣x−1∣=−3  no solution

x1y=5y=∣x1+5insertin(1)x1+∣∣x1+51∣=1x1+∣∣x1+4∣=1x1+x1+4=12x1∣=3nosolution

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