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Question Number 122120 by sina1377 last updated on 14/Nov/20

∫_0 ^3 (1/( (√y))).e^y dy

$$\underset{\mathrm{0}} {\overset{\mathrm{3}} {\int}}\frac{\mathrm{1}}{\:\sqrt{{y}}}.{e}^{{y}} {dy} \\ $$

Answered by Bird last updated on 14/Nov/20

I =∫_0 ^3  (e^y /( (√y)))dy  ⇒I =_((√y)=x)    ∫_0 ^(√3)  (e^x^2  /x)(2xdx)  =2∫_0 ^(√3)  e^x^2  dx =2∫_0 ^(√3) Σ_(n=0) ^∞  (x^(2n) /(n!))dx  =2Σ_(n=0) ^∞  (1/(n!))∫_0 ^(√3)  x^(2n) dx  =2Σ_(n=0) ^∞  (1/(n!))[(1/(2n+1)) x^(2n+1) ]_0 ^(√3)   =2 Σ_(n=0) ^∞  (1/((2n+1)n!))((√3))^(2n+1)   =2(√3)Σ_(n=0) ^∞   (3^n /((2n+1)n!))

$${I}\:=\int_{\mathrm{0}} ^{\mathrm{3}} \:\frac{{e}^{{y}} }{\:\sqrt{{y}}}{dy}\:\:\Rightarrow{I}\:=_{\sqrt{{y}}={x}} \:\:\:\int_{\mathrm{0}} ^{\sqrt{\mathrm{3}}} \:\frac{{e}^{{x}^{\mathrm{2}} } }{{x}}\left(\mathrm{2}{xdx}\right) \\ $$$$=\mathrm{2}\int_{\mathrm{0}} ^{\sqrt{\mathrm{3}}} \:{e}^{{x}^{\mathrm{2}} } {dx}\:=\mathrm{2}\int_{\mathrm{0}} ^{\sqrt{\mathrm{3}}} \sum_{{n}=\mathrm{0}} ^{\infty} \:\frac{{x}^{\mathrm{2}{n}} }{{n}!}{dx} \\ $$$$=\mathrm{2}\sum_{{n}=\mathrm{0}} ^{\infty} \:\frac{\mathrm{1}}{{n}!}\int_{\mathrm{0}} ^{\sqrt{\mathrm{3}}} \:{x}^{\mathrm{2}{n}} {dx} \\ $$$$=\mathrm{2}\sum_{{n}=\mathrm{0}} ^{\infty} \:\frac{\mathrm{1}}{{n}!}\left[\frac{\mathrm{1}}{\mathrm{2}{n}+\mathrm{1}}\:{x}^{\mathrm{2}{n}+\mathrm{1}} \right]_{\mathrm{0}} ^{\sqrt{\mathrm{3}}} \\ $$$$=\mathrm{2}\:\sum_{{n}=\mathrm{0}} ^{\infty} \:\frac{\mathrm{1}}{\left(\mathrm{2}{n}+\mathrm{1}\right){n}!}\left(\sqrt{\mathrm{3}}\right)^{\mathrm{2}{n}+\mathrm{1}} \\ $$$$=\mathrm{2}\sqrt{\mathrm{3}}\sum_{{n}=\mathrm{0}} ^{\infty} \:\:\frac{\mathrm{3}^{{n}} }{\left(\mathrm{2}{n}+\mathrm{1}\right){n}!} \\ $$

Answered by Dwaipayan Shikari last updated on 14/Nov/20

∫_0 ^3 Σ_(n=0) ^∞ (y^(n−(1/2)) /(n!))  Σ_(n=0) ^∞ ∫_0 ^3 (y^(n−(1/2)) /(n!))=2Σ_(n=0) ^∞ (3^(n+(1/2)) /(n!(2n+1)))  2(√3)Σ_(n=0) ^∞ (3^n /(n!(2n+1)))

$$\int_{\mathrm{0}} ^{\mathrm{3}} \underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{{y}^{{n}−\frac{\mathrm{1}}{\mathrm{2}}} }{{n}!} \\ $$$$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\int_{\mathrm{0}} ^{\mathrm{3}} \frac{{y}^{{n}−\frac{\mathrm{1}}{\mathrm{2}}} }{{n}!}=\mathrm{2}\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{3}^{{n}+\frac{\mathrm{1}}{\mathrm{2}}} }{{n}!\left(\mathrm{2}{n}+\mathrm{1}\right)} \\ $$$$\mathrm{2}\sqrt{\mathrm{3}}\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{3}^{{n}} }{{n}!\left(\mathrm{2}{n}+\mathrm{1}\right)} \\ $$

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