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Question Number 122142 by A8;15: last updated on 14/Nov/20

Answered by ebi last updated on 14/Nov/20

$$y=mx+c$$$$m=\frac{N\mathrm{\Sigma }\left(xy\right)-\mathrm{\Sigma }x\mathrm{\Sigma }y}{N\mathrm{\Sigma }{x}^2-{\left(\mathrm{\Sigma }x\right)}^2}$$$$c=\frac{\mathrm{\Sigma }y-m\mathrm{\Sigma }x}{N}$$$$\left|\begin{array}{c}x\\ -1\\ 0\\ 1\\ \mathrm{\Sigma }x=0\end{array}\right|\left|\begin{array}{c}y\\ 3\\ 2\\ 4\\ \mathrm{\Sigma }y=9\end{array}\right|\left|\begin{array}{c}{x}^2\\ 1\\ 0\\ 1\\ \mathrm{\Sigma }{x}^2=2\end{array}\right|\left|\begin{array}{c}xy\\ -3\\ 0\\ 4\\ \mathrm{\Sigma }xy=1\end{array}\right|$$$$N=3(no.ofdata)$$$$$$$$\therefore m=\frac{3\left(1\right)-\left(0\right)\left(9\right)}{3\left(2\right)-{\left(0\right)}^2}=\frac{1}{2}$$$$c=\frac{9-\frac{1}{2}\left(0\right)}{3}=3$$$$$$$$a+b=m+c=\frac{1}{2}+3=\frac{7}{2}\left(B\right)$$$$$$$$$$

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