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Question Number 122203 by help last updated on 14/Nov/20

Commented by Dwaipayan Shikari last updated on 14/Nov/20

$$K^{2}x+8y=30$$$$Kx+8y=10$$$$x(K^2-K)=20\Rightarrow K^2=\frac{20}{x}+K$$$$K=\frac{1+\sqrt{1+\frac{80}{x}}}{2}$$$$x=1K=5\left(Notsatisfies\right)$$$$x=10K=2\left(Satisfies\right)$$$$So{K}^2=4$$

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