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Question Number 122409 by help last updated on 16/Nov/20

Answered by sewak last updated on 17/Nov/20

Solun.:  Let  no. of  tickets sold to audit  be x.   and cenior audit be y.  We have, no. of ticket sold to child=95  From 1^(st)  condition,        x+y+95= 340  or, x=245−y...(i)  From 2^(nd)  condition,         95>y and 95<x  or, y<x     Now,  To get least value of x we put y=0   which also satisfy 2^(nd )  condition.  then, x=245−=245  where, 95<245 and  0<245  Hence, the least possible no. of audit   tickets sold on friday is 245.

$$\mathrm{Solun}.: \\ $$$$\mathrm{Let}\:\:\mathrm{no}.\:\mathrm{of}\:\:\mathrm{tickets}\:\mathrm{sold}\:\mathrm{to}\:\mathrm{audit}\:\:\mathrm{be}\:\mathrm{x}.\: \\ $$$$\mathrm{and}\:\mathrm{cenior}\:\mathrm{audit}\:\mathrm{be}\:\mathrm{y}. \\ $$$$\mathrm{We}\:\mathrm{have},\:\mathrm{no}.\:\mathrm{of}\:\mathrm{ticket}\:\mathrm{sold}\:\mathrm{to}\:\mathrm{child}=\mathrm{95} \\ $$$$\mathrm{From}\:\mathrm{1}^{\mathrm{st}} \:\mathrm{condition}, \\ $$$$\:\:\:\:\:\:\mathrm{x}+\mathrm{y}+\mathrm{95}=\:\mathrm{340} \\ $$$$\mathrm{or},\:\mathrm{x}=\mathrm{245}−\mathrm{y}...\left(\mathrm{i}\right) \\ $$$$\mathrm{From}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{condition},\: \\ $$$$\:\:\:\:\:\:\mathrm{95}>\mathrm{y}\:\mathrm{and}\:\mathrm{95}<\mathrm{x} \\ $$$$\mathrm{or},\:\mathrm{y}<\mathrm{x}\:\:\: \\ $$$$\mathrm{Now}, \\ $$$$\mathrm{To}\:\mathrm{get}\:\mathrm{least}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}\:\mathrm{we}\:\mathrm{put}\:\mathrm{y}=\mathrm{0}\: \\ $$$$\mathrm{which}\:\mathrm{also}\:\mathrm{satisfy}\:\mathrm{2}^{\mathrm{nd}\:} \:\mathrm{condition}. \\ $$$$\mathrm{then},\:\mathrm{x}=\mathrm{245}−=\mathrm{245} \\ $$$$\mathrm{where},\:\mathrm{95}<\mathrm{245}\:\mathrm{and}\:\:\mathrm{0}<\mathrm{245} \\ $$$$\mathrm{Hence},\:\mathrm{the}\:\mathrm{least}\:\mathrm{possible}\:\mathrm{no}.\:\mathrm{of}\:\mathrm{audit}\: \\ $$$$\mathrm{tickets}\:\mathrm{sold}\:\mathrm{on}\:\mathrm{friday}\:\mathrm{is}\:\mathrm{245}. \\ $$$$\:\:\:\:\:\: \\ $$

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