Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 122468 by SOMEDAVONG last updated on 17/Nov/20

$$\mathrm{I}.\int \sin {(3-\mathrm{cosx})}^4\mathrm{dx}=?$$

Answered by Dwaipayan Shikari last updated on 17/Nov/20

$$\int sinx{(3-cosx)}^{4}dx3-cosx=t\Rightarrow sinx=\frac{dt}{dx}$$$$\int t^{4}dt=\frac{1}{5}{t}^5+C=\frac{1}{5}{(3-cosx)}^5+C$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com