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Question Number 122514 by hedaru last updated on 17/Nov/20

Commented by liberty last updated on 18/Nov/20

$$\mathrm{A}=\mathrm{P}(1+3.\frac{8}{100})=2000(1.24)=2480$$$$\mathrm{CI}=2480-2000=480$$$$2000\times 1.24$$$$2480.0$$

Answered by physicstutes last updated on 17/Nov/20

$$\left(8\right)\left(\mathrm{a}\right)a_1=7$$$$T_{10}=a_1+9d=7+9d$$$$T_{20}=a_1+19d=7+19d$$$$d=\mathrm{common}\mathrm{difference}.$$$$S_n=\frac{n}{2}(T_{10}+T_{20})$$$$\Rightarrow 1155=\frac{11}{2}(7+9d+7+9d)$$$$d=\frac{98}{9}$$

Answered by physicstutes last updated on 17/Nov/20

$$\mathrm{Compound}\mathrm{interest}=A\mathrm{mount}-\mathrm{principal}$$$$\mathrm{where}\mathrm{Amount}A=P{(1+\frac{r}{100})}^n$$$$\Rightarrow A=\left(2000\right){(1+\frac{8}{100})}^3=2519$$$$\Rightarrow CI=2519-2000=519$$

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