Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 122523 by greg_ed last updated on 17/Nov/20

Answered by 676597498 last updated on 17/Nov/20

A=((x+x^2 )/(x^2 −x))=((x(1+x))/(x(x−1)))=((x+1)/(x−1)) ∀x≥0 or A=((−x+x^2 )/(x^2 −−x))=((x(x−1))/(x(x+1)))=((x−1)/(x+1)) ∀x<0

A=x+x2x2−x=x(1+x)x(x−1)=x+1x−1∀x⩾0orA=−x+x2x2−−x=x(x−1)x(x+1)=x−1x+1∀x<0

Commented by greg_ed last updated on 17/Nov/20

thank u

thanku

Commented by MJS_new last updated on 17/Nov/20

not ∀x≥0 / ∀x<0 but ∀x≥0∧x≠1 / ∀x<0∧x≠−1

not∀x⩾0/∀x<0but∀x⩾0∧x≠1/∀x<0∧x≠−1

Answered by mr W last updated on 17/Nov/20

A=((∣x∣+∣x∣^2 )/(∣x∣^2 −∣x∣))=((1+∣x∣)/(∣x∣−1))=(2/(∣x∣−1))+1

A=∣x∣+∣x∣2∣x∣2−∣x∣=1+∣x∣∣x∣−1=2∣x∣−1+1

Commented by greg_ed last updated on 17/Nov/20

ok !

ok!

Terms of Service

Privacy Policy

Contact: info@tinkutara.com