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Question Number 122729 by bemath last updated on 19/Nov/20

 Given lim_(x→c)  sin ((1/x)) = a and    lim_(x→c) ( sin^2 ((1/x))−4sin ((1/x))+1 )=−2  find the value of a.

$$\:{Given}\:\underset{{x}\rightarrow{c}} {\mathrm{lim}}\:\mathrm{sin}\:\left(\frac{\mathrm{1}}{{x}}\right)\:=\:{a}\:{and}\: \\ $$$$\:\underset{{x}\rightarrow{c}} {\mathrm{lim}}\left(\:\mathrm{sin}\:^{\mathrm{2}} \left(\frac{\mathrm{1}}{{x}}\right)−\mathrm{4sin}\:\left(\frac{\mathrm{1}}{{x}}\right)+\mathrm{1}\:\right)=−\mathrm{2} \\ $$$${find}\:{the}\:{value}\:{of}\:{a}. \\ $$

Answered by liberty last updated on 19/Nov/20

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