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Question Number 122773 by solstis last updated on 19/Nov/20

Answered by MJS_new last updated on 19/Nov/20

$$\frac{451}{225}-\frac{2}{5}=\frac{451}{5\times 45}-\frac{2}{5}=\frac{451}{5\times 45}-\frac{2\times 45}{5\times 45}=$$$$=\frac{451-2\times 45}{5\times 45}=\frac{361}{225}$$$$\mathrm{no}\mathrm{other}\mathrm{form}\mathrm{to}\mathrm{resolve}\mathrm{it}.\mathrm{we}\mathrm{can}\mathrm{only}\mathrm{add}$$$$\mathrm{or}\mathrm{subtract}\mathrm{fractions}\mathrm{with}\mathrm{the}\mathrm{same}\mathrm{denominator}$$

Commented by solstis last updated on 19/Nov/20

$$\mathrm{one}\mathrm{million}\mathrm{thank}!!$$

Commented by MJS_new last updated on 19/Nov/20

$$\frac{a}{b}\pm \frac{c}{d}=\frac{ad\pm bc}{bd}$$$$\mathrm{if}b=n\beta \mathrm{and}d=n\delta$$$$\frac{a}{n\beta }\pm \frac{c}{n\delta }=\frac{a\delta \pm c\beta }{n\beta \delta }$$$$$$$$\frac{a}{b}\times \frac{c}{d}=\frac{ac}{bd}$$$$\frac{a}{b}\mathbf{÷}\frac{c}{d}=\frac{a}{b}\times \frac{d}{c}=\frac{ad}{bc}$$

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