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Question Number 122773 by solstis last updated on 19/Nov/20

Answered by MJS_new last updated on 19/Nov/20

((451)/(225))−(2/5)=((451)/(5×45))−(2/5)=((451)/(5×45))−((2×45)/(5×45))=  =((451−2×45)/(5×45))=((361)/(225))  no other form to resolve it. we can only add  or subtract fractions with the same denominator

$$\frac{\mathrm{451}}{\mathrm{225}}−\frac{\mathrm{2}}{\mathrm{5}}=\frac{\mathrm{451}}{\mathrm{5}×\mathrm{45}}−\frac{\mathrm{2}}{\mathrm{5}}=\frac{\mathrm{451}}{\mathrm{5}×\mathrm{45}}−\frac{\mathrm{2}×\mathrm{45}}{\mathrm{5}×\mathrm{45}}= \\ $$$$=\frac{\mathrm{451}−\mathrm{2}×\mathrm{45}}{\mathrm{5}×\mathrm{45}}=\frac{\mathrm{361}}{\mathrm{225}} \\ $$$$\mathrm{no}\:\mathrm{other}\:\mathrm{form}\:\mathrm{to}\:\mathrm{resolve}\:\mathrm{it}.\:\mathrm{we}\:\mathrm{can}\:\mathrm{only}\:\mathrm{add} \\ $$$$\mathrm{or}\:\mathrm{subtract}\:\mathrm{fractions}\:\mathrm{with}\:\mathrm{the}\:\mathrm{same}\:\mathrm{denominator} \\ $$

Commented by solstis last updated on 19/Nov/20

one million thank!!

$$\mathrm{one}\:\mathrm{million}\:\mathrm{thank}!! \\ $$

Commented by MJS_new last updated on 19/Nov/20

(a/b)±(c/d)=((ad±bc)/(bd))  if b=nβ and d=nδ  (a/(nβ))±(c/(nδ))=((aδ±cβ)/(nβδ))    (a/b)×(c/d)=((ac)/(bd))  (a/b)÷(c/d)=(a/b)×(d/c)=((ad)/(bc))

$$\frac{{a}}{{b}}\pm\frac{{c}}{{d}}=\frac{{ad}\pm{bc}}{{bd}} \\ $$$$\mathrm{if}\:{b}={n}\beta\:\mathrm{and}\:{d}={n}\delta \\ $$$$\frac{{a}}{{n}\beta}\pm\frac{{c}}{{n}\delta}=\frac{{a}\delta\pm{c}\beta}{{n}\beta\delta} \\ $$$$ \\ $$$$\frac{{a}}{{b}}×\frac{{c}}{{d}}=\frac{{ac}}{{bd}} \\ $$$$\frac{{a}}{{b}}\boldsymbol{\div}\frac{{c}}{{d}}=\frac{{a}}{{b}}×\frac{{d}}{{c}}=\frac{{ad}}{{bc}} \\ $$

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