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Question Number 122776 by shaker last updated on 19/Nov/20

Answered by mathmax by abdo last updated on 19/Nov/20

$$\mathrm{without}\mathrm{using}\mathrm{anything}....!$$

Answered by kaivan.ahmadi last updated on 19/Nov/20

$${lim}_{x\to 0}\left(\frac{2x^4}{3x^6}\right)+\left(\frac{3x^2}{3x^6}\right)-\left(\frac{3{tg}^{2}x}{3x^6}\right)=$$$${lim}_{x\to 0}\frac{2}{3x^2}+\frac{1}{x^4}-\frac{1}{x^4}={lim}_{x\to 0}\frac{2}{3x^2}=+\mathrm{\infty }$$

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