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Question Number 122799 by aurpeyz last updated on 19/Nov/20
Answered by liberty last updated on 19/Nov/20
lettingu=1+3x−1⇒du=−3x−2dxL(x)=−13∫u23du=−13×35u53+cthus∫31x−2(1+3x−1)23dx=−15[(1+3x−1)53]13=−15[243−4163]=25[2163−43]=25[423−43]
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