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Question Number 122884 by CanovasCamiseros last updated on 20/Nov/20

Commented by CanovasCamiseros last updated on 20/Nov/20

$$\mathit{N}\mathit{e}\mathit{e}\mathit{d}\mathit{h}\mathit{e}\mathit{l}\mathit{p}\mathit{f}\mathit{o}\mathit{r}\mathit{t}\mathit{h}\mathit{i}\mathit{s}\mathit{p}\mathit{l}\mathit{e}\mathit{a}\mathit{s}\mathit{e}$$

Answered by MJS_new last updated on 20/Nov/20

$$\sqrt{{\mathrm{e}}^x}={\mathrm{e}}^{\frac{x}{2}}$$$$\int \sqrt{{\mathrm{e}}^x}dx={2\mathrm{e}}^{\frac{x}{2}}+C$$

Commented by MJS_new last updated on 20/Nov/20

$$\mathrm{it}\mathrm{is}\mathrm{the}\mathrm{same}.$$$$\sqrt{a}=a^{\frac{1}{2}}$$$${\left(a^b\right)}^c=a^{bc}$$$$\sqrt{{\mathrm{e}}^x}={\left({\mathrm{e}}^x\right)}^{\frac{1}{2}}={\mathrm{e}}^{\frac{x}{2}}$$

Commented by CanovasCamiseros last updated on 20/Nov/20

$$\mathit{W}\mathit{h}\mathit{y}\mathit{i}\mathit{s}\mathit{i}\mathit{t}\mathit{t}\mathit{h}\mathit{a}\mathit{t}\mathit{i}\mathit{g}\mathit{e}\mathit{t}2\sqrt{{\mathit{e}}^{\mathit{x}}}+\mathit{C}?$$

Commented by CanovasCamiseros last updated on 21/Nov/20

$$\mathit{O}\mathit{o}\mathit{o}\mathit{o}\mathit{o}\mathit{h}!\mathit{I}\mathit{g}\mathit{e}\mathit{t}\mathit{i}\mathit{t}\mathit{s}\mathit{i}\mathit{r}...\mathit{T}\mathit{h}\mathit{a}\mathit{n}\mathit{k}\mathit{y}\mathit{o}\mathit{u}\mathit{s}\mathit{o}\mathit{m}\mathit{u}\mathit{c}\mathit{h}!$$

Commented by CanovasCamiseros last updated on 21/Nov/20

$$\mathit{O}\mathit{o}\mathit{o}\mathit{o}\mathit{o}\mathit{h}!\mathit{I}\mathit{g}\mathit{e}\mathit{t}\mathit{i}\mathit{t}\mathit{s}\mathit{i}\mathit{r}...\mathit{T}\mathit{h}\mathit{a}\mathit{n}\mathit{k}\mathit{y}\mathit{o}\mathit{u}\mathit{s}\mathit{o}\mathit{m}\mathit{u}\mathit{c}\mathit{h}!$$

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