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Question Number 122973 by bemath last updated on 21/Nov/20

Answered by mr W last updated on 21/Nov/20

$$12.$$$$\frac{10+C_2^3\times 10}{{10}^3}=\frac{1}{25}=4\mathrm{\%}$$

Commented by bemath last updated on 21/Nov/20

$$yes...$$

Answered by mr W last updated on 21/Nov/20

$$13.$$$$a)$$$$(C_3^{12}-C_1^{10})\times 3!=1260$$$$b)$$$$(C_1^{10}+C_3^{10})\times 3!=780$$$$c)$$$$C_2^{11}\times 3!=330$$$$d)$$$$C_2^{11}\times 2!+C_3^{11}\times 3!=1430$$$$e)$$$$C_1^{10}\times 3!=60$$$$f)$$$$(1+2\times 9)\times 3!=114$$

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