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Question Number 123145 by aurpeyz last updated on 23/Nov/20

$$\int \frac{x^3}{{(3x^4-6)}^6}dx$$

Commented by benjo_mathlover last updated on 23/Nov/20

$$\delta \left(x\right)=\frac{1}{12}\int \frac{d(3x^4-6)}{{(3x^4-6)}^6}=\frac{1}{12}\int u^{-6}du$$$$=-\frac{1}{60}{u}^{-5}+c=-\frac{1}{60{(3x^4-6)}^5}+c$$

Answered by Dwaipayan Shikari last updated on 23/Nov/20

$$\int \frac{x^3}{{(3x^4-6)}^6}dx=\frac{1}{12}\int \frac{dt}{t^6}=-\frac{1}{60t^5}=-\frac{1}{60{(3x^4-6)}^5}$$

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