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Question Number 123155 by Algoritm last updated on 23/Nov/20

Answered by Dwaipayan Shikari last updated on 23/Nov/20

$$f\left(x\right)(1+2x+3x^2+4x^3+...)=1$$$$f^{\prime }\left(x\right)(1+2x+3x^2+..)+f\left(x\right)(1+2+6x+..)=0$$$$f^{\prime }\left(0\right)+3f\left(0\right)=0$$$$f^{\prime }\left(0\right)=-3f\left(0\right)$$

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