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Question Number 123200 by aurpeyz last updated on 23/Nov/20

find the area bounded by the curve  x^3 =5y and straight line x=3y−4

$${find}\:{the}\:{area}\:{bounded}\:{by}\:{the}\:{curve} \\ $$$${x}^{\mathrm{3}} =\mathrm{5}{y}\:{and}\:{straight}\:{line}\:{x}=\mathrm{3}{y}−\mathrm{4} \\ $$

Commented by benjo_mathlover last updated on 24/Nov/20

Commented by benjo_mathlover last updated on 24/Nov/20

nothing the area bounded   by the curve x^3 =5y and x=3y−4

$${nothing}\:{the}\:{area}\:{bounded}\: \\ $$$${by}\:{the}\:{curve}\:{x}^{\mathrm{3}} =\mathrm{5}{y}\:{and}\:{x}=\mathrm{3}{y}−\mathrm{4} \\ $$

Commented by aurpeyz last updated on 24/Nov/20

thank you

$${thank}\:{you} \\ $$

Answered by MJS_new last updated on 24/Nov/20

there′s no bounded area because the curve  and the line only got one intersection

$$\mathrm{there}'\mathrm{s}\:\mathrm{no}\:\mathrm{bounded}\:\mathrm{area}\:\mathrm{because}\:\mathrm{the}\:\mathrm{curve} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{line}\:\mathrm{only}\:\mathrm{got}\:\mathrm{one}\:\mathrm{intersection} \\ $$

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