find the area bounded by the curve x^3 =5y and straight line x=3y−4


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Question Number 123200 by aurpeyz last updated on 23/Nov/20

$f i n d t h e a r e a b o u n d e d b y t h e c u r v e$ $x^{3} = 5 y a n d s t r a i g h t l i n e x = 3 y - 4$
Commented by benjo_mathlover last updated on 24/Nov/20

Commented by benjo_mathlover last updated on 24/Nov/20

$n o t h i n g t h e a r e a b o u n d e d$ $b y t h e c u r v e x^{3} = 5 y a n d x = 3 y - 4$
Commented by aurpeyz last updated on 24/Nov/20

$t h a n k y o u$
	Answered by MJS_new last updated on 24/Nov/20

	${there}^{'} s no bounded area because the curve$ $and the line only got one intersection$
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